B. if the two surge protectors are arranged in parallel, what is the probability that a voltage surge will not damage the television?

Let's first set the two surge protectors as p and q. In order to solve this question we would also need another variable: the probability x of working correctly when a voltage surge occurs. So, the probability that the voltage surge will not damage the TV is: 1 - 0.06^2 divide by x^2.