In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an average speed of 0.5 meter per hour fast than the tortoise, crosses the finish line 1 minute before the tortoise. What are the average speeds of the tortoise and the hare?

Question

Mathematics

Landyn Kline

20 December, 06:08

In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an average speed of 0.5 meter per hour fast than the tortoise, crosses the finish line 1 minute before the tortoise. What are the average speeds of the tortoise and the hare?

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Answers (1)

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Dillan Compton · Answer 1

We know that:

time=distance/speed

if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min

18/x=23+18 / (x+1/120)

solving for x we get:

x=0.08 m/min

speed of hare is:

(0.08+1/120) = 0.088 m/min