Olutions At the snack bar, hot dogs cost $4 each and bottled water costs $2 each. In the first business hour of the day, less than $12 worth of hot dogs and water were sold. Which are reasonable solutions for this situation if x represents the number of hot dogs sold and y represents the number of bottles of water sold? Check all that apply.

Question

Mathematics

Wilson

Yesterday, 17:29

Olutions At the snack bar, hot dogs cost $4 each and bottled water costs $2 each. In the first business hour of the day, less than $12 worth of hot dogs and water were sold. Which are reasonable solutions for this situation if x represents the number of hot dogs sold and y represents the number of bottles of water sold? Check all that apply.

+3

Answers (1)

Know the Answer?

Damaris · Answer 1

To solve the problem it is trial and error since we don’t know how many hotdogs and bottled water was sold. To trim down to problem, negative values and decimal values are not included because there is no negative amount and a decimal amount.

The equation is

4x + 2y > 12

At (0,6)

4 (0) + 2 (6) > 12

12 > 12 so it is wrong

At (2,1)

4 (2) + 2 (1) > 12

10 > 12 correct

At (1, 3)

4 (1) + 2 (3) > 12

10 > 12 correct

At (2,2)

4 (2) + 2 (2) > 12

12> 12 wrong