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10 June, 12:04

write a quadratic function in standard form with zeros 6 and - 8

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  1. 10 June, 13:31
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    x=6 or x=-8 x-6=0 or x+8=0 (x-6) (x+8) = 0 x^2+8x-6x-48=0 x^2+2x-48=0 So the function f (x) = x^2+2x-48 has the zeros 6 and - 8
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