Ask Question
3 June, 00:01

The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square kilometers, find the dimensions of the rectangle.

+3
Answers (1)
  1. 3 June, 01:25
    0
    Let x = the length

    2x - 6 = the width as given in the description.

    Area of a rectangle is length * width. Now we plug in.

    108 = x (2x - 6)

    108 = 2x² - 6x

    We are going to get all terms on the same side and factor.

    2x² - 6x - 108 = 0

    Factor out and divide each term by a GCF of 2 to get:

    x² - 3x - 54 = 0

    x² + 6x - 9x - 54 = 0

    x (x + 6) - 9 (x + 6) = 0

    Your factors are (x + 6) (x - 9) = 0. Now we set each binomial equal to zero. This gives us x = - 6 and x = 9. Distance cannot be measure in negative numbers so we know to use x = 9 to find our measurements.

    The length (x) is 9 kilometers. The width (2x - 6) is 12 kilometers when you plug in 9 where the x is.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square kilometers, find the dimensions of the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers