Ask Question
14 September, 21:56

Solving quadratic equations: x² + 6x + 5 = 45

+5
Answers (1)
  1. 14 September, 23:21
    0
    First bring all terms to one side left equal to zero

    X^2 + 6x - 40

    Now we need to factor this, meaning find 2 binomials that when multiplied result in the original.

    Start with (x) (x) because x*x = x^2

    The last part is negative, so we can turn it into (x+) (x-)

    Now we need to find two numbers that add to 6 and multiply to - 40

    The numbers that work are 10 and - 4

    Now we put those in to get (x+10) (x-4) = 0

    Now it is factored.

    Because they equal 0, that means that one or both of the expressions inside the parentheses must equal zero

    So we can split it up into x+10=0 and x-4=0

    Solving for those we get x=-10 or x=4

    Final answer:

    X=-10 or x=4
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solving quadratic equations: x² + 6x + 5 = 45 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers