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26 February, 22:29

The resting heart rates for 80 women aged 46-55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. Assuming a 90% confidence level, what is the margin of error for the population mean?

0.66

1.10

1.31

1.73

+1
Answers (1)
  1. 27 February, 00:29
    0
    The margin of error can be calculated using the formula:

    1. ME = critical value * standard deviation / sqrt (sample size)

    2. ME = critical value * standard error

    Since we are given the standard deviation and the sample size, we can use equation 1. The critical value is always fixed and can be determined using a t or z graph. For 90% confidence level, the CV is 1.645.

    ME = 1.645 (6) / sqrt80 = 1.1
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