Ask Question
19 January, 11:23

A Ferris wheel with a radius of 13 m is rotating at a rate of one revolution every 2 minutes. How fast is a rider rising when the rider is 18 m above ground level?

+5
Answers (1)
  1. 19 January, 11:34
    0
    Assume the center of ferris wheel is 13 m from ground

    h = elevation of rider

    A = angle of elevation of rider with respect to center of ferris wheel

    dA/dt = 2pi/2 = pi rads/min

    h = 13sin (A) + 13

    dh/dt = 13cos (A) dA/dt

    when h = 18 m

    18 = 13sin (A) + 13

    sin (A) = 5/13

    cos (A) = sqrt (1 - (5/13) ^2)

    cos (A) = 12/13

    dh/dt = 13*12/13*pi

    dh/dt = 12pi m/min
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A Ferris wheel with a radius of 13 m is rotating at a rate of one revolution every 2 minutes. How fast is a rider rising when the rider is ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers