For this question, Determine if the equation is always, sometimes, or never true. If the equation is sometimes true, determine the numbers that make it true.

The equation is: 6y + 5 = 4y + 5 and - 2 (6 - 10n) = 10 (2n - 6)

If I've understood correctly,

First eq'n:

True only when y = 0

[simply rearrange the eq'n to solve for y]

Second eq'n:

Never true

[when you expand and simplify you will get some two different integers equated to each other which is incorrect; the integers will vary depending on how and how much simplifying you do]