For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. How much time did the bicyclist spend on the entire trip? Let t be the time (in hours), and find t if:

If v = 15 km/h We have:

d1 = 30 km

d2 = 17 km

Since speed = distance/time follows time = distance/speed.

The total time of the entire trip is is the sum of the time of the first 30 km and the time of the remaining 17 km:

d1/v + d2 / (v + 2) = 30/15 + 17 / (15 + 2) = 2 + 1 = 3 hours

The answer is t=3hours