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Today, 10:04

What's the answer for the sum of three consecutive numbers is 126. What is the smallest of the three numbers

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  1. Today, 11:08
    0
    To solve this problem, start with the smallest and call it n. The next three numbers are n+1 and n+2, so the sum of these numbers is:

    n + (n+1) + (n+2) = 126.

    This equation reduces to:

    3n+3 = 126 subtracting 3 from either side makes it

    3n = 123 and dividing either side by 3 means

    n = 41

    The smallest is 41 so the largest is 43
  2. Today, 11:46
    0
    126 divided into 3 equal parts is 42 in each part.

    Lay the parts out in a row on the table.

    Take 1 away from one part, and drop it onto a different part.

    Now you have your 3 consecutive numbers, made from the 3 equal parts of 126.

    They are 41, 42, and 43.
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