There are four families attending a concert together. each family consists of 1 male and 2 females. in how many ways can they be seated in a row of twelve seats i

Each family sits together. They all sit on adjacent 3 seats. 3! x 3! X 3! X 3! And they can be rearranged in 4! Ways.

Total ways = (3!) ^4 x 4!=6^4 x 24=31104

There are 31104 ways they can be seated in a row of twelve seats