How many multiples of 5 are there between 199 and 1,198? Hint: an = a1 + d (n - 1), where a1 is the first term and d is the common difference.

An=a1+d (n-1)

A1=200 since that's the first term that can be a multiple of 5

N=? That's what we need to find

An=1195 since that's the last multiple of 5 that we can use

D=5

Plug in

1195=200+5 (n-1)

-200 both sides

995=5 (n-1)

Distribute 5 to n-1

995=5n-5

+5 both sides

1000=5n

:5 both sides

N=200 there are 200 multiples of 5 in between 199 and 1198