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7 July, 20:32

A student's calculation was found to have a 35.5% error, and his experimental measurement was 15.6 cm. What are the two possible values for the actual measurement?

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  1. 7 July, 23:56
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    Let the two possible actual measurements be. x' and 'y', where x is a measurement less than 15.6 and y is a measurement more than 15.6

    x + 35.5% of x = 15.6

    y - 35.5% of y

    35.5% as decimal is 0.355

    x + 0.355x = 15.6, and

    y - 0.355y = 15.6

    Solving x + 0.355x = 15.6

    1.355x = 15.6

    x = 15.6:1.355 = 11.53

    Solving y - 0.355x = 15.6

    0.645y = 15.6

    y = 15.6 - 0.645

    y = 24.19

    Two possible measurements are 11.53 and 24.19
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