Ask Question
27 October, 18:47

Tom walked at a consistent pace from the economy parking garage to the airport terminal. He stood on a a moving sidewalk for 2/5 of the route, moving at twice his normal walking pace. He made the trip in 6 minutes. On his return trip, the moving sidewalk was out of order, so how long did it take him to walk back?

+1
Answers (1)
  1. 27 October, 22:46
    0
    Let x be the number of minutes for his normal walk

    On the way to the airport, for the 2/5 (or 40%) of his route, his speed is twice faster. Hence, the number of x should be divided to 2. The rest of the route (60%) was on his normal pace. The total minutes is 6. The equation is:

    0.4 (x:2) + 0.6x = 6

    Solving for x, the number of minutes for his normal walk is 7.5 minutes.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Tom walked at a consistent pace from the economy parking garage to the airport terminal. He stood on a a moving sidewalk for 2/5 of the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers