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9 June, 04:32

At 10:00 a. m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p. m. they meet. If one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?

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  1. 9 June, 05:17
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    A = speed of one boy

    a + 3 = speed of 2nd boy

    d = speed X time ... time is 3 hrs

    68 = 3a + 3 (a + 3)

    6a = 59

    a = 59/6 = 9 5/6 miles per hour

    a + 3 = 12 5/6 miles per hou
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