In a paddock there are emus and wombats. If there are 52 heads and 148 feet, how many emus are in the paddock?

Then x+y=52 ... (1)

and 2x + 4y = 148 ... (2)

multiplying equation (1) by 2

we get

2x + 2y = 104 ... (3)

subtracting equation (3) from equation (2)

2y=44

y=22

that is x=52-22=30

there are 30 emus and 22 wombats

Emu have 2 feet and 1 head

wombat has 4 feet and 1 head

E = emu

W = Wombat

E + W = 52

2E + 4W = 148

E = 52-W

2 (52-W) + 4W = 148

104-2W + 4W = 148

104 + 2W = 148

2W = 44

W = 44/2 = 22

E = 52-22 = 30

there are 30 Emus