Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach?

0.8 ft

1.6 ft

9.8 ft

19.6 ft

Approximately, how long does it take until the soccer ball hits the ground again?

0.6 sec

0.8 sec

1.6 secs

2.8 secs

Use the formula for a problem like this, which is h (t) = - 16t^2 + vt + s, where t = time in air, v = starting upward velocity, and s = the objects starting height. Since the ball is starting from the ground (s), the starting height is 0, And the ball's initial velocity (v) 25 feet per second, you plug in 0 for S, and you plug in 25 for v. - 16t^2 + (25) t + 0. Since s is equal to zero, it can be removed to leave

-16t^2 + 25t. To put the quadratic equation in standard form, make it equal to zero. 0 = - 16t^2 + 25t. Now solve by factoring. First, find a gcf.

0 = - 16t^2 + 25t

They are both only divisible by their shared "t", therefore, the gcf is t.

Now divide both terms by t.

t (-16 + 25). To continue with the problem, you must set each factor equal to zero. t = 0 and - 16 + 25 = 0. Subtract the 25 from both sides to balance the equation. - 16 = - 25. divide both sides by - 16 to get - 25/-16 = 1.56

This rounds to 1.60 or 1.6

Therefore, the answer is C.