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30 November, 04:11

A store sells forks for $3.50 each, spoons for $3.80 each, and knives for $4.25 each. Ken wants to have a ratio of forks to spoons to knives of 5:4:2. He can spend a maximum of $300. What is the greatest number of forks Ken can buy?

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  1. 30 November, 04:48
    0
    Forks to spoons to knives ... 5:4:2 ... added = 11 ... so 5/11 of the total amount is spent on forks, 4/11 of the total amount is spent on spoons, and 2/11 of the total amount is spent on knives.

    so if there is a total amount of 300 (maximum) ...

    5/11 * 300 = 1500/11 = 136.36 is spent on forks

    4/11 * 300 = 1200/11 = 109.09 is spent on spoons

    2/11 * 300 = 600/11 = 54.55 is spent on knives

    so if $ 136.36 is what can be spent on forks, and forks cost $ 3.50 each ... then at most, he can get : 136.36 / 3.50 = 38.96 rounds to 38 forks <==
  2. 30 November, 07:45
    0
    5 x 3.50 = $17.50

    4 x 3.80 = $15.20

    2 x 4.25 = $8.50

    17.50 + 15.20 + 8.50 = $41.20

    Each bundle containing 5 forks, 4 spoons and 2 knives would cost him $41.20. To keep the ratio he would buy this "bundle" as many times as the $300 limit allowed, meaning you must divide 300 by 41.20

    300/41.20 = 7.28

    Fractions are irrelevant because it would mean not being able to buy some of the items, which would mess up the ratio. So 7 is the amount of times he can buy 5 forks, 4 sponsors and 2 knifes. So the amount of forks is:

    7x5 = 35 forks
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