Determine whether the function below is an even function, an odd function, both, or neither.

f (x) = (x+5) ^2

Question

Mathematics

Skyler Andrade

25 March, 04:11

Determine whether the function below is an even function, an odd function, both, or neither.

f (x) = (x+5) ^2

+4

Answers (1)

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Saniyah Cole · Answer 1

A function is even if, for each x in the domain of f, f ( - x) = f (x). The even functions have reflective symmetry through the y-axis. A function is odd if, for each x in the domain of f, f ( - x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.

f (x) = (x + 5) ^ 2

f (x) = x ^ 2 + 10x + 25

f (-x) = (-x + 5) ^ 2

f (x) = x ^ 2 - 10x + 25

the function does not comply with the definitions.

The function is NOT even

The function is not odd

answer

neither

Determine whether the function below is an even function, an odd function, both, or neither.f (x) = (x+5) ^2

Determine whether the function below is an even function, an odd function, both, or neither.

f (x) = (x+5) ^2