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8 August, 14:08

What are the solutions of the equation x^2+4x=96

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  1. 8 August, 15:47
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    X² + 4x = 96

    Subtract 96 from both sides to get the equation equal to zero:

    x² + 4x - 96 = 0

    We can solve for x either by factoring or by using the Quadratic Formula. Let's attempt to factor first. To factor, find two numbers whose sum is 4 and whose product is - 96. Since 96 is negative, the pair will be one positive and one negative (a positive times a negative is always negative). Let's start listing addends of 4 and calculating their product.

    12 + (-8) = 4; 12 * (-8) = - 96

    The pair is 12 and - 8. The factored polynomial is (x + 12) (x - 8). To find x, find the zeros.

    x + 12 = 0

    x = - 12

    x - 8 = 0

    x = 8

    Answer:

    x = - 12 and x = 8
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