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Mathematics
Javier Good
15 April, 23:15
Squareroot (y-1) + 3 = y
+3
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Ricky Chase
15 April, 23:34
0
Note:xy means x times y and x (y) means the same thing
so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0
squareroot (y-1) + 3=y
isolate the squareroot
subtrac 3 from boht sides
squareroot (y-1) = y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot (y-1)) ^2 = (y-3) ^2
(y-1) = (y-3) (y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get - 7
the answer is - 2 and - 5
0 = (y-5) (y-2)
therfore
y-5=0
and/or
y-2=0
therefor
y=5 or/and 2 might work
let's try out 2
square root (2-1) + 3=2
square root (1) + 3=2
1+3=2
false
so 2 doesn't work
let's try 5
squareroot (5-1) + 3=5
squareroot (4) + 3=5
2+3=5
5=5
true
y=5
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