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4 September, 16:41

Which equation, when graphed, has x-intercepts at (-1,0) and (-5,0) and a y-intercepts at (0,-30) ?

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  1. 4 September, 19:03
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    Using the x intercepts, we know that the graph will be of a parabola and that y=0 at x=1 and x=5. By the y-intercept, we know that the parabola will be concave down.

    We will start with the equation - (x+1) (x+5) which would satisfy the requirements of the x-intercepts and make the parabola concave down. The y-intercept, however, is (0,-5). To change the y-intercept, we will need to stretch the graph which can be done by multiplying the entire equation by 6.

    The equation you are looking for is "-6 (x+1) (x+5)"
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