Jimmy drove to his cabin on the lake and back. it took 0.6 hours longer to go there than it did to come back. the average speed on the trip there was 46 km/h. the average speed on the way back was 52 km/h. how many hours did the trip there take

Question

Mathematics

Zoe Wilkins

8 August, 11:06

Jimmy drove to his cabin on the lake and back. it took 0.6 hours longer to go there than it did to come back. the average speed on the trip there was 46 km/h. the average speed on the way back was 52 km/h. how many hours did the trip there take

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Answers (1)

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Ronnie Bauer · Answer 1

To answer this item, we let x be the distance that Jimmy drove from his origin and back. Given the speeds, the time it takes for him to travel to and fro are,

t1 = x / 46

t2 = x / 52

respectively.

The equation that would best represent the scenario is,

x/46 - x/52 = 0.6

The value of x from the equation is 239.2.

The trip there takes x/46 which is equal to 239.2/46 which is also equal to 5.2 hours. The travel from the cabin back took 4.6 hours.