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Mathematics
Marley Frazier
15 July, 12:09
Factorise 45x^2 - 46x + 8
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BatMan
15 July, 14:16
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The way to do this is if the equtation is in
ax^2+bx+c form
then multiply a and c together and get
a times c=y times z where y+z=b then make the form into
ax^2+yx+zx+c so
a=45
b=-46
c=8
a time c=45 times 8=360
then find what 2 numbers add up to - 48 and multiply to get 360
the numbers must be both negative because only same signs multiplied by each other can result in a positive number
factor 360
360,1
180,2
120,3
90,4
72,5
60,6
45,8
40,9
36,10
30,12
24,15
20,18
now add and find which add up to 48
360+1=361
180+2=182
120+3=123
90+4=94
72+5=77
60+6=66
45+8=53
40+9=49
36+10=46 match
30+12=42
24+15=39
20+18=38
the numbers are - 36 and - 10
split it up
45x^2-10x-36x+8
group
(45x^2-10x) + (-36x+8)
factor out the common factors
(5x) (9x-2) + (-4) (9x-2)
reverse distributive property which is ab+ac=a (b+c)
(5x-4) (9x-2)
tada, it's factored
factored form is (5x-4) (9x-2)
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