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17 November, 10:31

Given that f (x) = x² + 5x, evaluate f (-2).

-6

-14

7

+1
Answers (1)
  1. 17 November, 14:16
    0
    F (x) = x^2 + 5x ... evaluate f (-2) ... so sub in - 2 everywhere there is an x

    f (-2) = - 2^2 + 5 (-2)

    f (-2) = 4 - 10

    f (-2) = - 6 <==
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