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25 April, 14:04

Question 1:

y=5^4x-3 what is the ordered pair? (its 5 to the power of 4)

question 2:

which ordered pair makes the equation true?

2y=-5x-4

a. (-2,3)

b. (1,-4)

c. (0,2)

d. (-1,1)

+3
Answers (1)
  1. 25 April, 15:44
    0
    Question 1:

    I'm actually not sure which term you ment exactly, so I calculated the solution for three possible variations of your term, depending on how one sets the brackets.

    To calculate an ordered pay just set x or y to some value, insert it into the equation and you get the solution for the other variable.

    In these calculations I always picked x so values would get eliminated or as close to 0 as possible to make it easier.

    variation 1 of term:

    y = (5^4) * (x-3)

    insert x=3

    y = (5^4) * (3-3) = = (5^4) * 0=0

    pair: (3,0)

    variation 2 of term:

    y = (5^4) * x-3

    insert x=0:

    y = (5^4) * 0-3=0-3=-3

    pair: (0,-3)

    variation 3 of term:

    y=5^ (4*x-3)

    insert x=1:

    y=5^ (4*1-3) = 5^1=5

    pair: (1,5)

    question 2:

    2y=-5x-4

    just insert the pairs as (x, y) into the equation:

    a. (-2,3)

    2*3=-5*-2-4

    6=10-4 yes

    b. (1,-4)

    2*-4=-5*1-4

    -8=-9 no

    c. (0,2)

    2*2=-5*0-4

    4=-4 no

    d. (-1,1)

    2*1=-5*-1-4

    2=5-4 no
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