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17 May, 18:58

Solve log (base 2) (x+1) + log (base 2) (x-5) = 4

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  1. 17 May, 21:56
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    (x+1) (x-5) = 2^4=16

    x^2 - 4x - 5 = 16

    x^2-4x-21=0

    x = - 3 or 7

    but we would choose 7 as the answer as - 3 gives negative value at (x+1) and we know that log of negative number is not defined.
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