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12 February, 19:44

A company wants to estimate the mean net weight of all 32-ounce packages of its yummy taste cookies at 95% confidence. it is known that the standard deviation of net weights is 0.1 ounce. the sample size that will yield the margin of error within 0.02 ounces of the population mean is

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  1. 12 February, 21:28
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    Standard deviation = σ = 0.1

    Confidence interval = 95% = 0.95

    Significance level=α = 1-0.95 = 0.05

    α/2 = 0.025

    At α/2 z (α/2) = 1.960 [from statistic table]

    Now,

    the sample size at error of 0.02 is

    0.02=z (α/2) σ/√n

    0.02 = (1.960) * (0.1) / √n

    5/49 = 1/√n

    √n=49/5

    n=96.04

    n should be 96 or greater
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