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17 October, 19:31

A jet plane is descending at a rate of 200 feet per second from an altitude of 36000 feet let x represent the number of seconds of descent and y represent the jet plane's altitude in feet.

Which expression represents this situation?

A. y = 200x - 36000

B. y = 200x + 36000

C. y = - 200x - 36000

D. y = - 200x + 36000

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Answers (2)
  1. 17 October, 21:25
    0
    Jane's plane will be modeled using linear equation given by:

    y=ax+b

    where:

    a=slope=rate

    b=y-intercept or initial valuegiven:

    from the question

    a=200 ft per second

    b=36000 ft

    thus the expression representing the situation will be:

    y=200x+36000

    where x is time in seconds

    thus the answer is:

    B. y = 200x + 36000
  2. 17 October, 22:23
    0
    Rate of descend = 200 ft/sec

    In x second, the plane will have descended by 200*x ft = 200x ft

    The altitude of the plane, y after x seconds will be 36000 - 200x. That is,

    y = 36000-200x = - 200x + 36000.

    Therefore, the correct expression representing this situation is D.
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