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Mathematics
Jack Gardner
12 September, 05:48
Let f (x) = 2x-3/9 and g (x) = 9x+3/2
Find (f o g) (x)
Find (f o g) (x)
+2
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Hudson Mcdonald
12 September, 07:41
0
These seem tough, but they are not that bad.
(f o g) (x)
That means to take function g when x = x (It just means that you don't need to do anything with the function) and substitute it into function f wherever there is a x value. (So basically g becomes what x equals)
Here is a visual representation of it.
(f o g) (x) = 2 (9x + (3/2)) - (3/9)
We need to distribute the 2 to everything inside the parenthesis.
(f o g) (x) = 18x + (6/2) - (3/9)
Let's simplify the fraction on the right and left, then find a common denominator so we can add / subtract the two fractions.
(f o g) (x) = 18x + (3) - (1/3)
(f o g) (x) = 18x + (9/3) - (1/3)
Combine like terms.
(f o g) (x) = 18x + (8/3)
Our final answer is:
(f o g) (x) = 18x + 8/3
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