Ask Question
26 May, 00:59

Factor. 25m^100 - 121n^16

+4
Answers (1)
  1. 26 May, 03:20
    0
    This is a difference of squares. Difference of squares factor like this.

    a^2 - b^2 = (a + b) (a - b)

    In your question all 4 factors must be perfect squares in order to use this property.

    25 = 5*5

    m^100 = m^50 * m^50

    121 = 11 * 11

    n^16 = n^8 * n*8

    All four parts are perfect squares as required.

    a = 5m^50

    b = 11n^8

    a^2 - b^2 = (5m^50 - 11n^8) (5m^50 + 11n^8)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Factor. 25m^100 - 121n^16 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers