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Mathematics
Perla Patton
6 June, 14:54
Write the function in vertex form.
y=4x2 - 8x + 5
+2
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2
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Hamza Gross
6 June, 16:02
0
a=4, b=-8, c=5
h=-b/2a = - (-8) / 2 (4)
8/8=h=1
K = a (h) ^2+b (h) + c
K = 4 (1) ^2-8 (1) + 5
K = 4-8+5
K = 1, Vertex Form: a (x-h) ^2+k
Vertex Form: Y = 4 (X - (1) ^2+K
Y = 4 (x-1) ^2+1
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Porter Wright
6 June, 17:42
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You will have to complete the square
factor the 4 out of the first two terms
y = 4 (x^2 - 2x) + 5
x^2 - 2x + 1 = (x - 1) ^2
we want what we have to look like this
the difference between (x^2 - 2x) and (x^2 - 2x + 1) is the + 1
so we add a 1 and subtract a 1 to keep balance
y = 4 (x^2 - 2x + 1 - 1) + 5
y = 4 (x^2 - 2x + 1) - 4 + 5 [moved the extra - 1 out of it and distributive property]
y = 4 (x - 1) ^2 + 1 [factored and added like terms]
y = 4 (x-1) ^2 + 1
or
y - 1 = 4 (x-1) ^2
is now in vertex form.
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