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6 June, 14:54

Write the function in vertex form.

y=4x2 - 8x + 5

+2
Answers (2)
  1. 6 June, 16:02
    0
    a=4, b=-8, c=5

    h=-b/2a = - (-8) / 2 (4)

    8/8=h=1

    K = a (h) ^2+b (h) + c

    K = 4 (1) ^2-8 (1) + 5

    K = 4-8+5

    K = 1, Vertex Form: a (x-h) ^2+k

    Vertex Form: Y = 4 (X - (1) ^2+K

    Y = 4 (x-1) ^2+1
  2. 6 June, 17:42
    0
    You will have to complete the square

    factor the 4 out of the first two terms

    y = 4 (x^2 - 2x) + 5

    x^2 - 2x + 1 = (x - 1) ^2

    we want what we have to look like this

    the difference between (x^2 - 2x) and (x^2 - 2x + 1) is the + 1

    so we add a 1 and subtract a 1 to keep balance

    y = 4 (x^2 - 2x + 1 - 1) + 5

    y = 4 (x^2 - 2x + 1) - 4 + 5 [moved the extra - 1 out of it and distributive property]

    y = 4 (x - 1) ^2 + 1 [factored and added like terms]

    y = 4 (x-1) ^2 + 1

    or

    y - 1 = 4 (x-1) ^2

    is now in vertex form.
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