Determine values of c and d for √which the equation √ (3x-1) - √ (cx + d) = 0 has no solution.
I added √ (cx + d) to both sides and squared them ... 3x-1 = cx + d
rearranged to get 3x - cx = d + 1; then factored out x to get x (3 - c) = d + 1
then divided x = (d + 1) / (3 - c) therefore c ≠ 3 what about d?
I'm not sure what question is asking when looking for c and d
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