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27 May, 10:14

What kind of solution (s) does ax^2-bx+c=0 have if b^2-4ac<0?

a. two real solutions

b. one real solution

c. one complex solution

d. two complex solutions

+1
Answers (2)
  1. 27 May, 12:20
    0
    Liike the other user said

    when the discriminant is less than 0, you get 2 complex roots

    D is the answer
  2. 27 May, 12:26
    0
    The discriminant is the value that is b^2 - 4ac.

    When this number is <0 there will be 2 complex solutions. Letter D.

    You would be taking the sqrt of a negative number resulting in a

    " + - i sqrt of a number"
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