A company is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x.

Which equation can be used to determine the greatest possible volume of the cardboard box?

(15-2x) (22-2x) x=0

(22x-15) (15x-22) = 0

(x-15) (x-22) x=0

(15-x) (22-x) x=0

It would be the top one. You didn't give the dimensions of the piece of cardboard being worked with but anyone can solve for the general case ...

If the cardboard is L by W, the volume created by cutting out squares, x, from the corners will be:

V = (L-2x) (W-2x) x

So only the first choice is of the form just above ...