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1 January, 08:34

2log4-log3+2logx-4=0

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  1. 1 January, 09:34
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    2log4-log3+2logx-4=0

    I assume it's find x

    2log4=log4^2=log16

    2logx=logx^2

    -log3=log3^ (-1) = log1/3

    log (16x^2) / 3=4

    base is unknown, so if it's different just plug it in for the lower values of 10

    we'll just assume it's common log's base is 10

    10^4 = (16x^2) / 3

    30000=16x^2

    x^2=30000/16

    x = (30000^1/2) / 4 which is about 43.301
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