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26 December, 22:30
Given cos q = - 1/5 and tan q> 0, find sin q
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Jordon Pollard
26 December, 23:15
0
cos (q) = ⁻¹/₅
cos⁻¹[cos (q) ] = cos⁻¹ (⁻¹/₅)
q ≈ 1.54
tan (q) > 0
tan⁻¹[tan (q) ] > tan⁻¹ (0)
q > 0
tan (1.54) > 0
0.03 > 0
sin (q) = sin (1.54)
sin (q) ≈ 0.03
Since tan (1.54) is equal to sin (1.54), they are both greater than zero.
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