A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.

Question

Mathematics

Branson Benson

19 August, 23:18

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.

+1

Answers (2)

Know the Answer?

Ryan Ali · Answer 1

a) L+L+w+w=302

48+w+48+w+w+w=302

96+2w=302

2w=206

w=103

final answer: width is 103feet

length = L=48+w=48+103=151feet

Raelynn Preston · Answer 2

The first equation would be w+49=l. The second equation would be 2w+2l=302. Now, substitute l in the second equation with the first equation and solve.

2w+2 (w+49) = 302

2w+2w+98=302

4w=204

w=51

l=51+49

l=100

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feeta) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.b) Use the method of substitution to solve the system.

A rectangular garden is 49 feet longer than it is wide. Its perimeter is 302 feet

a) let w be the width of the garden and L be the length. Write a system of linear equations whose solution gives the width and length of the garden.

b) Use the method of substitution to solve the system.