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Cassidy Riggs
29 November, 14:34
What's the product for (5v-1) (4v+3)
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Marlie Hendrix
29 November, 16:37
0
You need to use the foil process
20v^2+15v-4v-3
20v^2+11v-3
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Esteban Stafford
29 November, 17:03
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Multiply everything out to get
(5v-1) (4v+3) = 20v²+15v-4v-3
then combine like terms
20v²+11v-3
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