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Mathematics
Haylie Ortega
9 October, 00:44
Find the roots of the equation x3-3x^2+x+5
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Kathy Curry
9 October, 04:42
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X^3-3x^2+x+5 = (x+1) (x^2-4x+5)
(x+1) (x^2-4x+5) = 0
x+1=0→x+1-1=0-1→x=-1
x^2-4x+5 different to zero
The root of the equation is x=-1
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