What are the zeros of the function f (x) = 2x^2+16x-9

So the step process for this is to factor it out so this is a complex trinomial so u will have to multiply 2 by - 9 and the rest should be in your notes.

then once u factor it out you rearrange those two factored brackets and example of this would be

(x+3) (2x+1)

so x+3=0

therefore x=-3. you bring the 3 over to where the zero is and change the sign

for 2x+1=0

2x=-1

2x/2=-1

x=-1/2

so for this one you isolate for x and in order to get rid of 2x you divide by 2 for both