Solve the equation by completing the square m^2+6m-77=-5

Maybe you thought about this:

m^2+6m-77+5=0 = > m^2+6m-72=0 = > m^2 + 2*3*m+3^2-3^2-72=0

=> m^2+2*3*x+3^2 = (m+3) ^2 this is the complete square of the binomial, we will still keep it = >

(m+3) ^2 - 9 - 72=0 = > (m+3) ^2 - 81 = 0 = > (m+3) ^2 - 9^2 = 0

Now we got the difference squares, it mean a^2 - b^2 = (a-b) (a+b)

In according to this = > (m+3-9) (m+3+9) = 0 = >

(m-6) (m+12) = 0 = > m-6=0 or m+12=0 = > m1=6 or m2 = - 12!

Are you satisfied with this solution?