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17 May, 10:16

The mean amount of time needed to microwave thaw a particular frozen dinner in preparation for convection cooking is 5.68 minutes. the standard deviation of thaw times is 0.95 minutes. what proportion of the meals will take between 4.36 and 7 minutes to thaw?

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  1. 17 May, 13:23
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    We need to determine the values of the z-scores of the given data.

    (4.36 minutes)

    z-score = (4.36 - 5.68) / 0.95 = - 1.39

    Which has an equivalent percentage of 8.2%.

    (7 minutes)

    z-score = (7 - 5.68) / 0.95 = 1.39

    Which has an equivalent percentile of 92%.

    Subtracting the two values will give us an answer of 83.8%.
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