A student must take one physics, one chemistry, and one mathematics course during their junior year of high school. There are three courses to choose from for physics (P1, P2, P3), two courses to choose from for chemistry (C1, C2), and two courses to choose from for mathematics (M1, M2). How many possible combinations are there for the three physics, chemistry, and mathematics courses a student could select?

Question

Mathematics

Matthew

13 April, 22:13

A student must take one physics, one chemistry, and one mathematics course during their junior year of high school. There are three courses to choose from for physics (P1, P2, P3), two courses to choose from for chemistry (C1, C2), and two courses to choose from for mathematics (M1, M2). How many possible combinations are there for the three physics, chemistry, and mathematics courses a student could select?

+1

Answers (1)

Know the Answer?

Bennett Lin · Answer 1

I'll write out one list of possible combinations as an example. Suppose we're looking at all paths following a choice of P1. Then we have:

P1 C1 M1

P1 C1 M2

P1 C2 M1

P1 C2 M2

So there are 4 possible choices with P1. Since there are 3 choices of P, there are 3*4 total combinations, or 12. In general, you can multiply the number of possibilities together to see how many total combinations can occur, I just wanted to illustrate why that works.