Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants

Question

Mathematics

Rolando Villanueva

15 May, 02:02

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants

+3

Answers (1)

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Love · Answer 1

Expanding the right side:-

5x^2 + Ax - 7 = Bx^2 + 4Bx + 4B + C

Equating coefficients of x^2:-

B = 5

Equating coefficients of x:-

A = 4B

so

A = 4*5 = 20

Equating constants terms

-7 = 4B + C = 20 + C

C = - 27

A=20, B = 5 and C = - 27

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + Cwhere A, B, C are constants

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants