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9 November, 06:30

A rectangular garden is 28 feet long. If you walk diagonally across the garden, you would walk 35 feet. How many feet wide is the garden?

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Answers (2)
  1. 9 November, 07:31
    0
    21, I used Pythagorean Therom: a^2 + b^2 = c^2

    a=28 b=? c=35

    25^2 + b^2 = 35^2

    Evaluate exponents

    784 + b^2 = 1225

    -784 - 784

    b^2=441

    Take square root of both sides.

    b=21
  2. 9 November, 09:08
    0
    This is a great place to apply the Pyth. Theorem. Let the width be W.

    Then W^2 + 28^2 = 35^2.

    Solving this, we get W^2 = 441. Taking the positive square root, we get

    W = 21 ft
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