Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = () 2 16y^6 = () 2

Then use a2 - b2 = (a - b) (a + b).

Show your work.

9x^6 - 16y^6 =

Question

Mathematics

Guest

17 November, 20:58

Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = () 2 16y^6 = () 2

Then use a2 - b2 = (a - b) (a + b).

Show your work.

9x^6 - 16y^6 =

+4

Answers (1)

Know the Answer?

Boyer · Answer 1

See the equation they want you to use. factor to make it like that.

9 is 3^2 and 16 is 4^2

x^6 is (x^3) ^2

so for the answer. factor each term

9x^6 = (3x^3) ^2

16y^6 = (4y^3) ^2

see that "a" is 3x^3 and "b" is 4y^3? put it all together

= (3x^3 - 4y^3) (3x^3 + 4y^3)

Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = (__) 2 16y^6 = (__) 2Then use a2 - b2 = (a - b) (a + b).Show your work.9x^6 - 16y^6 =

Factor 9x^6 - 16y^6 completely. First factor each term. 9x^6 = () 2 16y^6 = () 2

Then use a2 - b2 = (a - b) (a + b).

Show your work.

9x^6 - 16y^6 =