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27 November, 10:24

What is the period of y=sin (3x)

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  1. 27 November, 14:16
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    The new period is 2/3 π.

    The period of the two elementary trig functions, sin (x) and cos (x) is 2π.

    If we multiply the input variable by a constant has the effect of stretching or contracting the period. If the constant, c>1 then the period is stretched, if c<1 then the period is contracted.

    We can see what change has been made to the period, T, by solving the equation:

    cT=2π

    What we are doing here is checking what new number, T, will effectively input the old period, 2π, to the function in light of the constant. So for our givens:

    3T=2π

    T=2/3 π

    Other method to solve this;

    sin3 x = sin (3x+2π) = sin [3 (x + 2π / 3) ] = sin3 x

    This means "after the arc rotating three time of (x + (2 π/3)), sin 3x comes back to its initial value"

    So, the period of sin 3x is 2π / 3 or 2/3 π.
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