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16 October, 00:21

Jill wants to make 15 no of a 40% acid solution by mixing together a 30% acid solution and a 60% acid solution. How much of each solution must she use?

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  1. 16 October, 01:22
    0
    X+y=15

    0.3x+0.6y=0.4*15=6

    solve the system of equation.

    Multiply equation one by 0.3: 0.3x+0.3y=4.5

    subtract the new from the second equation: 0.3y=1.5

    y=5

    x=10
  2. 16 October, 02:54
    0
    15 no? Don't recognize "no." I'll use "units" instead.

    Let f represent the volume of the 40% acid solution.

    Let t represent that of the 30% solution, and s that of the 60% solution.

    Then s + t = 15 units. Then, (15 units) - s = t

    0.30t + 0.60s = (15 units) (0.40)

    Mult. this by 100 to elim. fractions: 30t + 60s = 600

    Subst (15 units - s) for t, 30 (15-s) + 60s = 600

    4500 - 30s + 60s = 600

    30s = 150

    s = 5 units

    Then t = (15 units - 5 units) = 10 units.

    Use 10 units of the 30% solution and 5 units of the 60% solution.

    Check: Does (10) (.3) + (5) (.6) = (15) (.4) ? Yes
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